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  • 13-07-2019
  • Mathematics
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The probability of a basketball player making a free throw is 3/4. If the player attempts 11 free throws, what is the probability that exactly 5 are made?

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absor201
absor201 absor201
  • 16-07-2019

Answer:

0.0268.

Step-by-step explanation:

This question can be solved using the binomial theorem.

Total attempts = n = 11

Required attempts = r = 5

Probability of success = p = 3/4 = 0.75

Binomial Theorem formula:

P(X=r) = nCr * p^r * (1-p)^(n-r).

Substituting the values:

P(X=5) = 11C5 * 0.75^5 * 0.25^6 = 0.0268 (to the nearest 3 significant figures).

So the probability that exactly 5 free throws are made out of 11 is 0.0268!!!

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