Respuesta :

r3t40

[tex]

\dfrac{1}{x-1}-\dfrac{3}{x^2+2x-3} \\

\dfrac{1}{x-1}-\dfrac{3}{(x+3)(x-1)} \\

\dfrac{1\cdot(x+3)-3}{(x+3)(x-1)} \\

\dfrac{x+3-3}{(x+3)(x-1)} \\

\dfrac{x}{(x+3)(x-1)}

[/tex]

Hope this helps.

r3t40

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