Dariusco2019
Dariusco2019 Dariusco2019
  • 12-05-2019
  • Mathematics
contestada

Determine whether the function f(x)=|x|+x2+0.001 is even , odd or neither. 10 points

Determine whether the function fxxx20001 is even odd or neither 10 points class=

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blazing33
blazing33 blazing33
  • 12-05-2019

the answer is even is the right answer

Answer Link
kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 12-05-2019

ANSWER

even

EXPLANATION

The given function is

[tex]f(x) = |x| + {x}^{2} + 0.001[/tex]

If f(x) is even then f(-x) =f(x).

[tex]f( - x) = | - x| + {( - x)}^{2} + 0.001[/tex]

[tex]f( - x) = | x| + {x}^{2} + 0.001[/tex]

We can see that:

[tex]f( - x) = f(x)[/tex]

Hence the given function is even.

Answer Link

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