jomilojuangel
jomilojuangel jomilojuangel
  • 14-02-2019
  • Mathematics
contestada

if c and k are the roots of 6-x-x^2=0 find c + k. pls solve like a quadratic equation​

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5naka
5naka 5naka
  • 14-02-2019

by Viete's formula

c + k = - koef x/koef x²

= - (-1)/(-1) = -1

Answer Link
jimrgrant1 jimrgrant1
  • 14-02-2019

Answer:

c + k = - 1

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

Then the sum of the roots = - [tex]\frac{b}{a}[/tex] and

The product of the roots = [tex]\frac{c}{a}[/tex]

- x² - x + 6 = 0 is in standard form

with a = - 1, b = - 1 and c = 6

The roots are c and k, hence

c + k = - [tex]\frac{-1}{-1}[/tex] = - 1

Answer Link

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