kkeith121p6ujlt kkeith121p6ujlt

13-01-2019
Mathematics

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Write the following equation in standard form then solve. 6q^2-2q=5q^2-5q+28

Write the following equation in standard form then solve 6q22q5q25q28 class=

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jimrgrant1 jimrgrant1

15-01-2019

Answer:

q = -7, q = 4

Step-by-step explanation:

subtract 5q² - 5q + 28 from both sides to obtain standard form

q² + 3q - 28 = 0 ← in standard form

(q + 7)(q - 4) = 0 ← in factored form

equate each factor to zero and solve for q

q + 7 = 0 ⇒ q = - 7

q - 4 = 0 ⇒ q = 4

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