noahborel97
noahborel97 noahborel97
  • 12-09-2014
  • Mathematics
contestada

factor completely: 6m^2 - mn - 12n^2

factor completely 6m2 mn 12n2 class=

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Аноним Аноним
  • 12-09-2014
[tex]6m^2-mn-12n^2=6m^2+8mn-9mn-12n^2\\\\=2m(3m+4n)-3n(3m+4n)=\boxed{(3m+4n)(2m-3n)}[/tex]
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