valentinapiki valentinapiki
  • 15-11-2018
  • Mathematics
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What’s the inverse of k(x)= x-2/x

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Savageboyn
Savageboyn Savageboyn
  • 16-11-2018

[tex]k - 1(x) = \frac{x + \sqrt{x2 + 8} }{2} \: \frac{x - \sqrt{x2 + 8} }{2} [/tex]
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