ch3atlikeab022 ch3atlikeab022
  • 15-11-2018
  • Mathematics
contestada

1=(1-sin^2O)(1+tan^2O)

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LammettHash
LammettHash LammettHash
  • 15-11-2018

I believe the equation is

[tex]1=(1-\sin^2\theta)(1+\tan^2\theta)[/tex]

which is true for all [tex]\theta[/tex], so I guess you're supposed to show why (i.e. establish the identity). Recall that

[tex]\cos^2\theta+\sin^2\theta=1[/tex]

from which we can derive

[tex]\cos^2\theta=1-\sin^2\theta[/tex]

[tex]1+\tan^2\theta=\sec^2\theta[/tex]

So the original equation is equivalent to

[tex]1=\cos^2\theta\sec^2\theta[/tex]

and since [tex]\sec\theta=\dfrac1{\cos\theta}[/tex], the right side reduces to 1.

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