kila88uhg kila88uhg
  • 14-09-2018
  • Mathematics
contestada

how do you sovle 10-3x-1≥6x

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freshyinneedofhelp freshyinneedofhelp
  • 14-09-2018
you should move the 3x over to the 6x, making the equation
[tex]10 - 1 \geqslant 9x[/tex]
you then divide the 9 on both sides, making 9/9x become 1x or just x, and the other 9/9, which equals 1. overall, your final equation should be
[tex]x \leqslant 1[/tex]
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