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kanest kanest
  • 12-09-2018
  • Mathematics
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[Precalculus] Simplify:

Precalculus Simplify class=

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Аноним Аноним
  • 12-09-2018

Numerator:

Apply the definition of secant and cotangent:

[tex] \sec(x) = \dfrac{1}{\cos(x)},\ \cot(x) = \dfrac{\cos(x)}{\sin(x)} [/tex]

So, their product is

[tex] \dfrac{1}{\cos(x)} \times \dfrac{\cos(x)}{\sin(x)} = \dfrac{1}{\sin(x)} = \csc(x) [/tex]

Denominator:

Simply factor a 2 and use the fundamental trigonometric identity:

[tex] 2\cos^2(x)+2\sin^2(x) = 2(\cos^2(x)+\sin^2(x)) = 2\times 1 = 2 [/tex]

So, the answer is

[tex] \dfrac{\csc(x)}{2} [/tex]

Answer Link

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