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12-08-2018
Mathematics

contestada

Write x2 - 12x + 8 in vertex form.

a. (x-6)2 -28 = 0

b. (x-4)2 - 11 = 0

c. (x-4)2 - 13

d. (x-4)2 - 15

Respuesta :

13-08-2018

[tex] (*)\qquad(a-b)^2=a^2-2ab+b^2 [/tex]

[tex] x^2-12x+8=x^2-2\cdot x\cdot6+8=\underbrace{x^2-2\cdot x\cdot6+6^2}_{(*)}-6^2+8\\\\=(x-6)^2-28\to\boxed{a.} [/tex]

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