iamliyaharyonpda6ui iamliyaharyonpda6ui
  • 11-08-2018
  • Mathematics
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Given \tan A = \frac{7}{{24}}, find the cos B

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rejkjavik rejkjavik
  • 20-08-2018

We are given

[tex] tan(A)=\frac{7}{24} [/tex]

we know that

[tex] tan(A)=\frac{opposite}{adjacent} [/tex]

so, we get

opposite =7

adjacent=24

now, we can find hypotenuse

[tex] hypotenuse=\sqrt{7^2+24^2} [/tex]

[tex] hypotenuse=25 [/tex]

now, we can draw triangle and then switch vertices accordingly

we can find cos(B) using second triangle

[tex] cos(B)=\frac{adjacent}{hypotenuse} [/tex]

In second triangle:

adjacent=7

hypotenuse =25

so, we get

[tex] cos(B)=\frac{7}{25} [/tex]................Answer

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