mwheat3 mwheat3

14-07-2018
Mathematics

contestada

Given P(E or F) = 0.16, P(E) = 0.12, and P(F) = 0.17, what is P(E and F)?

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konrad509 konrad509

14-07-2018

[tex] P(E \cap F)=P(E)+P(F)-P(E \cup F)\\\\
P(E \cap F)=0.16+0.12-0.17=0.11
[/tex]

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