bbygirlmaddie
bbygirlmaddie
15-06-2018
Mathematics
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gmany
gmany
15-06-2018
[tex]\sqrt{68}=\sqrt{4\cdot17}=\sqrt4\cdot\sqrt{17}=2\sqrt{17}\\\\\text{Used:}\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}[/tex]
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