we know that volume of a cone=(1/3)*area of the base*height Let A----> area of the base h---> height of the cone V=(1/3)*A*h-----> h=3*V/A V=6 in³ so original cone 6=(1/3)*A*h----> h=18/A
Find the height of a cone with the same base diameter but a volume of only 3 cubic inches
h=3*V/A-----> h=3*3/A---> h=9/A so the height of the cone is half the original height
the answer is the height of the cone is half the original height
