kasandrabbustos kasandrabbustos
  • 14-05-2018
  • Mathematics
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Find vertical and horizontal asymtope for (x^2+2x-48)/x+8

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sqdancefan
sqdancefan sqdancefan
  • 14-05-2018
There are none.

[tex]y=\dfrac{x^{2}+2x-48}{x+8}=\dfrac{(x+8)(x-6)}{x+8}\\\\y=x-6[/tex]

The expression describes a straight line with a hole at x=-8 where it is undefined.
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