izazahmd7552 izazahmd7552 15-03-2024 Physics contestada A proton moves in a circular path perpendicular to a 2.09 T magnetic field. The radius of its path is 7.26 mm. Calculate the energy of the proton?a) 1.6910⁻¹⁵Jb) 3.3810⁻¹⁵ Jc) 6.7610⁻¹⁵Jd) 1.3510⁻¹⁴ J
